- #1
greg_rack
Gold Member
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- 79
- Homework Statement
- An object is thrown vertically upwards from ground level with an initial velocity of 40 ms–1.
2.0 seconds later another object is released from a height above the ground and falls vertically
from rest.
Both of the objects hit the ground at the same time.
From what height above the ground was the second object released?
- Relevant Equations
- ##v=v_{0}+at##
##\Delta x=\frac{v^2-v_{0}}{2a}##
First of all I have found the time taken by the first object to hit the ground back: ##\Delta t=2(\frac{v}{a})##.
Then, by subtracting 2 seconds to this quantity, I get the time in which the second object has accelerated in free fall, with terminal velocity ##v=at##.
Now, I find the distance traveled by the second object: ##\Delta x=\frac{v}{2a}##... but the result I get is wrong!
Then, by subtracting 2 seconds to this quantity, I get the time in which the second object has accelerated in free fall, with terminal velocity ##v=at##.
Now, I find the distance traveled by the second object: ##\Delta x=\frac{v}{2a}##... but the result I get is wrong!