Is the Ion Bound with this Energy Minimization?

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Minimizing energy with respect to 'a' leads to the equation E = (ħ²/m)a² - (11/8)e²a. The minimum value occurs at a = (11m/16ħ²)e², resulting in a negative energy value of -(11/16)²(me⁴/ħ²). A negative energy indicates that the ion is bound. According to the variational principle, since the upper bound is negative, the ion is confirmed to be bound.
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Homework Statement
There exists some ion with a hamiltonian H = H0 + H1. The expectation value of H0 is ## \frac{\hbar ^2}{m} a^2 - 2 e^2 a## and the expectation value of H1 is ##\frac{5}{8} e^2 a##, where ##a## is some parameter with units of inverse length. Is the ion bound?
Relevant Equations
H = H0 + H1
expectation value of H0 is ## \frac{\hbar ^2}{m} a^2 - 2 e^2 a##
expectation value of H1 is ##\frac{5}{8} e^2 a##
From what we did in class, I think we need to minimize the energy with respect to a.

Like ##E = \frac{\hbar ^2}{m} a^2 - 2 e^2 a + \frac{5}{8} e^2 a = \frac{\hbar ^2}{m} a^2 - \frac{11}{8} e^2 a ##, then minimize it

Finding the minimum value: ## - (\frac{11}{16})^2 \frac{m e^4}{\hbar^2} ## when ## a = \frac{11 m}{16 \hbar ^2} e^2 ##

I am not sure how to tell if this means the ion is bound or not?? The energy is negative, but does that help??
 
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Yes. According to variational principle $$E_g\leq <\text H>$$. Since tighetst upper bound you have founded is negative,it is bounded.
 

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