Finding instantaneous acceleration from a straight line on a velocity-time graph

[karaonstage]

How can you find the instantaneous accelertation of an object whose curve on the velocity-time graph is a straight line?

 

[James R]

a=dv/dt.

Acceleration is the gradient of the velocity-time curve at any point.

 

[apm]

acceleration = (velocity 2 - velocity 1)/ (time 2 -time1)

 

[bomba923]

How can you find the instantaneous accelertation of an object whose curve on the velocity-time graph is a straight line?

Only just a straight line? Then
$$\forall n > 1,\;\frac{{d^n v}}{{dt^n }} = 0$$
over the interval containing this line

*karaonstage, simply find the slope of this line, and you will thus calculate the acceleration of the object.
If the slope $= 0$, the object simply doesn't accelerate (travels at constant velocity).

 

[moose]

Above is correct. But next time, try to think to yourself, what is acceleration. Change in velocity over time, well, if you have a velocity vs time graph, than a change in velocity over time IS your slope.