Finding intersection of three planes

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    Intersection Planes
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Discussion Overview

The discussion revolves around finding the intersection of three planes defined by given normal vectors in a three-dimensional space. Participants explore the implications of the vectors being linear combinations of each other and the conditions under which the planes intersect, including a specific case where one vector is altered.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents the problem of finding the intersection of three planes defined by the vectors n1, n2, and n3.
  • Another participant suggests that the original n3 is a linear combination of n1 and n2, leading to the conclusion that the three planes do not intersect at a single point, but rather have pairwise intersections that form three parallel lines.
  • A different participant counters that the planes do intersect, but not at a single point, referencing the Rouché-Capelli theorem to support their claim.
  • One participant emphasizes that knowledge of linear algebra is not strictly necessary, suggesting that understanding systems of equations is sufficient to approach the problem.
  • Another participant reiterates that the original n3 being a linear combination of the others results in no unique solution, while the modified n3 would yield a unique solution due to the determinant of coefficients being non-zero.
  • There is a clarification that the three parallel lines could be coincident, indicating a potential overlap in the geometric interpretation of the planes.

Areas of Agreement / Disagreement

Participants express disagreement regarding the nature of the intersection of the planes. Some assert that the planes do not intersect at a single point, while others argue that they do intersect, albeit not uniquely. The discussion remains unresolved with competing views on the intersection properties.

Contextual Notes

There are limitations regarding the assumptions made about the linear combinations of the vectors and the implications for the intersection of the planes. The discussion also touches on the determinant of the coefficient matrix, which is central to understanding the uniqueness of solutions.

Tarrius
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Hi!

I'm having trouble with this question, any help would be much appreciated! :)

Q1: Given the three vectors:

n1 = (1, 2, 3)
n2 = (3, 2, 1)
n3 = (1, −2, −5)

Find the intersection of the three planes ni*x = 0. What happens if n3 = (1, −2, −4)? Why is this different?
 
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Are you familiar with vector spaces and matrix rank?
 
Tarrius said:
Hi!

I'm having trouble with this question, any help would be much appreciated! :)

Q1: Given the three vectors:

n1 = (1, 2, 3)
n2 = (3, 2, 1)
n3 = (1, −2, −5)

Find the intersection of the three planes ni*x = 0. What happens if n3 = (1, −2, −4)? Why is this different?
Your original n3=(1,-2,-5) = n2-2n1 so the three planes don't intersect. The pairwise intersections (of the planes) are 3 parallel lines.

The other n3 would work since it is not a linear combination of the others.
 
mathman said:
Your original n3=(1,-2,-5) = n2-2n1 so the three planes don't intersect.
Actually they do intersect, just not in a single point as can be shown by the Rouché-Capelli theorem.
 
You don't really need to know linear algebra- just the basics of systems of equations.
The planes defined by the first three vectors are
x+ 2y+ 3z= 0
3x+ 2y+ z= 0
x- 2y- 5z= 0.

Find the general solution to that system (there is NOT a unique solution because the determinant of coefficients is 0). What does that define, geometrically. The second set of equations do NOT have 0 determinant so have a unique solution. What that solution is should be obvious.
 
da_nang said:
Actually they do intersect, just not in a single point as can be shown by the Rouché-Capelli theorem.
I forgot that the three parallel lines could be coincident.
 

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