An electron, initially at rest, is accelerated through a potential difference of 600 V between two parallel plates.(adsbygoogle = window.adsbygoogle || []).push({});

The plate on the bottom is @ 0 V. The top plate is 600 V. And the distance between the two is 4.2 x 10^-2 m.

Calculate the kinetic energy gained.

Alright, so initially I was thinking the potential energy must be converted into kinetic energy, so I started using the conservation of energy formula and ended up with -U = Kf. Is electric potential difference the same as electric potential energy?

The answer's 9.6 x 10^-17 J btw. Can't figure out how!

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# Finding kinetic energy between parallel plates

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