Calculating Potential Difference in a Parallel Plate Apparatus

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Homework Help Overview

The problem involves calculating the potential difference in a parallel plate apparatus where an electron is injected through a positive plate and collides with a negative plate. The electron's initial and final speeds are provided, and the context is set in a vacuum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between kinetic energy and electric potential energy, questioning the calculations and assumptions made by the original poster. There are requests for detailed calculations and clarification on the concepts of kinetic and potential energy as the electron moves between the plates.

Discussion Status

The discussion is ongoing, with participants seeking to clarify the original poster's calculations and understanding of the energy concepts involved. Some guidance has been offered regarding the equations and the relationship between kinetic and potential energy, but no consensus has been reached on the correct approach or solution.

Contextual Notes

There is a mention of a specific answer from a textbook, which may influence the expectations of the participants. The original poster expresses uncertainty about their calculations, indicating potential gaps in understanding the energy transformations involved.

Poguer0170
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Homework Statement


an electron with a speed of 5x10^6 m/s is injected into a parallel plate apparatus, in a vacuum, through a hole in the positive plate. The electron collides with the negative plate at 1x10^6 m/s. What is the potential difference between the plates?

Homework Equations


E=1/2mv^2
E=qV

The Attempt at a Solution


I’m not quite sure what to do... i tried finding kinetic energy and setting it equal to the energy in the plates but that gave me a small answer (i checked in the back the answer is 68V)
 
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Can you show us your calculation, complete with units?
 
Perhaps you could show exactly how you got your answer and what it is. Then we can figure out what went wrong.
 
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Hello. Welcome to PF!

Poguer0170 said:

Homework Equations


E=1/2mv^2
E=qV
It will help to use more precise notation. As you know, (1/2)mv2 is the kinetic energy of a particle. So, you can write it as

KE = (1/2)mv2

And, qV is the electric potential energy of a particle with charge q when it is located at a point where the potential is V. So, write

PE = qV

The total energy of the particle at some location is Etot = KE + PE.
(I used the subscript tool on the toolbar to write Etot).

3. The Attempt at a Solution
I’m not quite sure what to do... i tried finding kinetic energy and setting it equal to the energy in the plates but that gave me a small answer (i checked in the back the answer is 68V)

When the electron is at any point in its movement between the plates, it will have a certain amount of KE and a certain amount of PE. Just to see if you are clear on some basics, please answer the following questions (yes or no).

(1) As the electron moves from one point to another, does the KE of the electron change?

(2) As the electron moves from one point to another, does the PE of the electron change?

(3) As the electron moves from one point to another, does Etot of the electron change?

[EDIT: I see that @jbriggs444 and @kuruman replied while I was writing my post. You may ignore my post if you wish.]
 
I suggest the following:
1. Write the Lorentz force: ##m_ea_x=q_eE_x## for electron traveling in positive x direction.
2. Use the fact ## \frac {d^2 x}{dt^2} = v_x \frac{dv_x}{dx}## .
3. Integrate and use the fact that the voltage is the E field times the plate separation..
4. Look up the mass to charge ratio of the electron.

peace,
Fred
 

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