Finding Kinetic Energy of a Collision

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SUMMARY

The discussion revolves around calculating the kinetic energy lost during a collision between a 900 kg car and a 2800 kg truck using the center-of-momentum frame. The initial kinetic energies are calculated using the formula K = P²/(2m), where P is the momentum. The total kinetic energy before the collision is the sum of the kinetic energies of both vehicles, and the problem requires determining the kinetic energy after the collision to find the energy lost.

PREREQUISITES
  • Understanding of kinetic energy calculations using K = P²/(2m)
  • Familiarity with momentum conservation principles
  • Knowledge of the center-of-momentum frame concept
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of the center-of-momentum frame in detail
  • Learn how to apply conservation of momentum in collisions
  • Explore examples of kinetic energy loss in inelastic collisions
  • Review problem-solving techniques for physics collision problems
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for examples of kinetic energy calculations in real-world scenarios.

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Homework Statement



A 900 kg car moving east at 31 m/s runs head-on into a 2800 kg truck moving west at 15 m/s. The vehicles stick together. Use the concept of the center-of-momentum frame to determine how much kinetic energy is lost.


Homework Equations



Kf= Ki(car) + Ki(truck)
K= P^2/(2m)

The Attempt at a Solution



Well I am having difficulty with this problem because I don't know which equations would be suitable for this problem.

Any ideas?
 
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How do you think you might go about converting things to the center of momentum frame?
 

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