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physjeff12
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Finding length of skid marks using fk
A 1000kg car traveling at a speed of 40m/s skids to a halt on wet concrete where µk = 0.60. How long are the skid marks?
(i know this an easy problem, but i am stuck when trying to find the length of the skid marks.)
Fg = mg = weight = normal force
fk = µkFN
Fg = 1000(9.8) = 9800 N, therefore the normal force = 9800N
µk = .60
fk = .60(9800)
fk = 5800 N
v0 = 40m/s
fk = 5880 N
Where do i go from here to find the distance of the skid marks?
i was thinking maybe using the formula, x = x0 + vt, but i am not sure
Homework Statement
A 1000kg car traveling at a speed of 40m/s skids to a halt on wet concrete where µk = 0.60. How long are the skid marks?
(i know this an easy problem, but i am stuck when trying to find the length of the skid marks.)
Homework Equations
Fg = mg = weight = normal force
fk = µkFN
The Attempt at a Solution
Fg = 1000(9.8) = 9800 N, therefore the normal force = 9800N
µk = .60
fk = .60(9800)
fk = 5800 N
v0 = 40m/s
fk = 5880 N
Where do i go from here to find the distance of the skid marks?
i was thinking maybe using the formula, x = x0 + vt, but i am not sure