Finding length of skid marks using f k

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Finding length of skid marks using fk

Homework Statement



A 1000kg car traveling at a speed of 40m/s skids to a halt on wet concrete where µk = 0.60. How long are the skid marks?

(i know this an easy problem, but i am stuck when trying to find the length of the skid marks.)

Homework Equations



Fg = mg = weight = normal force

fk = µkFN

The Attempt at a Solution



Fg = 1000(9.8) = 9800 N, therefore the normal force = 9800N
µk = .60

fk = .60(9800)
fk = 5800 N

v0 = 40m/s
fk = 5880 N

Where do i go from here to find the distance of the skid marks?

i was thinking maybe using the formula, x = x0 + vt, but i am not sure
 
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Welcome to PF!

Hi physjeff12! Welcome to PF! :wink:
physjeff12 said:
fk = 5880 N

Where do i go from here to find the distance of the skid marks?

i was thinking maybe using the formula, x = x0 + vt, but i am not sure

From fk, find the acceleration, and then use one of the standard constant acceleration equations. :smile:
 


tiny-tim said:
Hi physjeff12! Welcome to PF! :wink:From fk, find the acceleration, and then use one of the standard constant acceleration equations. :smile:

thanks :smile:

and how do i find the acceleration using fk? i don't know any formulas that connect acceleration with friction force.

EDIT: nvm, i am stupid. i found out how. F = ma :smile: