Finding Magnitude of Force of a Nucleus

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The discussion focuses on calculating the magnitude of the force exerted by a nucleus to stop a neutron within its diameter. The neutron's initial speed is given as 1.3 x 10^7 m/s, and the nucleus has a diameter of 1.3 x 10^-14 m. The user attempts to apply the equation v^2 = v0^2 - 2ad to find the acceleration and subsequently the force. However, they encounter errors in their calculations, particularly in squaring the velocity. The conversation highlights the importance of careful mathematical operations in solving physics problems.
AnkhUNC
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Homework Statement


A nucleus that captures a stray neutron [in a nuclear reactor, for example] must bring the neutron to a stop within the diameter of the nucleus by means of the strong force.That force, which "glues" the nucleus together, is approximately zero outside the nucleus. Suppose that a stray neutron with an initial speed of 1.3 x 107 m/s is just barely captured by a nucleus with a diameter of 1.3 x 10-14 m. Assuming the strong force on the neutron is constant, find the magnitude of that force. (The neutron's mass is 1.67x10-27 kg.)


Homework Equations





The Attempt at a Solution



So I do the following:

v^2 = v0^2-2ad -> 0^2 = 1.3*10^7 - 2a(1.3*10^-14)
a = -1.3*10^7/(2(1.3*10^-14)) = 2.20385 so * mass = 2.010423077E-5

But this is incorrect?
 
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Hi AnkhUNC,

It looks to me like you made some math errors in the last line of your work. It looks like you might not have squared the velocity, and maybe more after that.
 
Yeah I did I worked it out thanks
 
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