- #1

munkhuu94

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**magnitude of the "current" flowing around the nucleus in the Bohr mode**

## Homework Statement

According to the Bohr model, a hydrogen atom in its lowest energy state has a nucleus consisting of a single proton, which is orbited by a single electron. The speed of the electron is 2.19×106 m/s and the radius of its orbit (the "Bohr radiuis") is 5.29×10−11 m. What is the magnitude of the "current" flowing around the nucleus in the Bohr model?

radius=5.29e-11

v=2.19e6

## Homework Equations

equation used : I=nAvq ( i was surfing internet and found this equation, i couldn't find equation from the book)

2nd try: equation : I = e*w, where e is elementary charge and w is revs/s.

3rd try: J=I/A J is magnitude of current density.

## The Attempt at a Solution

1st: I= 1*2pi(5.29e-11)^2(2.19e6)(-1.6e-19)

I= -6.16e-30 A seems very wrong.

2nd;

e = 1.6022E-19

w = v/(2pi*r)

I = 9.46518E-4 A ( i found this on yahoo answers, but it wasn't right, and i never seen that equation before.)

3rd: I don't know how to find the current if i use this equation. Please help.