Finding Mass of an Object [Fluid Mechanics]

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SUMMARY

The discussion focuses on calculating the mass of lead required to submerge a wooden cube with an edge length of 20.0 cm and a density of 650 kg/m³ in water. The cube floats with a distance of 7.0 cm from its top surface to the water level. To achieve equilibrium, an additional mass of 2.80 kg of lead must be placed on the cube. The volume of the cube is confirmed to be 8000 cm³, which is essential for further calculations.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically buoyancy.
  • Knowledge of density calculations and the formula V = m/d.
  • Familiarity with volume calculations for geometric shapes, particularly cubes.
  • Basic grasp of equilibrium concepts in physics.
NEXT STEPS
  • Study Archimedes' principle and its applications in buoyancy.
  • Learn about the relationship between density, mass, and volume in fluid mechanics.
  • Explore the concept of equilibrium in floating and submerged objects.
  • Investigate the effects of adding mass to floating bodies in various fluids.
USEFUL FOR

This discussion is beneficial for students and professionals in physics, particularly those studying fluid mechanics, as well as engineers and educators involved in teaching buoyancy and density concepts.

Minihoudini
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A cube of wood having an edge dimension of 20.0 cm and a density of 650kg/m^3 floats on water. a) what is the distance from the horizontal top surface of the cube to the water level?
b)what mass of lead should be placed ont eh cube so that the top of the cube will be just level with the water?

A is 7.0cm
B is 2.80kg


Vfluid/Vobject= Dobject/Dfluid

I figured out how do to the first part but I am having trouble trying to find out part B.
I know you have to use V=m/d but the problem is I can't seem to find volume.
 
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What's the volume of a cube?
 
sorry its 8000cm^3
 

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