Finding max height and acceleration vector for projectile

[Vibhor]

Homework Statement

Homework Equations

The Attempt at a Solution

Maximum height attained by first projectile H = u²sin²θ/2g = 15m

If acceleration vector is assumed a = a_xi+a_yj , then at H √(a_x²+a_y²) = 50 .

Now I need to use the given conditions to come up with another equation . Not sure how to proceed .

Please help me with the problem .

 

[Doc Al]

Your attachment isn't viewable.

 

[Vibhor]

Please see if it is viewable now .

 

[Vibhor]

Could somebody help me with the problem .

 

[Doc Al]

Figure out the centripetal acceleration at that point. Hint: Use the fact that the first projectile is at its apex at the point H.

 

[Vibhor]

Hi Doc

Your suggestion has worked nicely .Thanks a lot .

I was just wondering what do we infer from the third line in the problem " such that the speed is increasing continuously ". We didn't make any use of it .

Your thoughts ?

 

[Doc Al]

I was just wondering what do we infer from the third line in the problem " such that the speed is increasing continuously ". We didn't make any use of it .

You make use of that fact in determining the direction of the horizontal acceleration component. It tells you that a_x is positive.

 

[Vibhor]

Thank you very much .