Finding max. height of object thrown vertically upard

  1. 1. The problem statement, all variables and given/known data
    An object is thrown vertically upward such that it has a speed of 47 m/s when it reaches two thirds of its maximum height above launch point. Find maximum height h.



    2. Relevant equations

    V^2-Vo^2 = 2gh
    or
    V^2-Vo^2 = 2g(1/3H)?

    3. The attempt at a solution
    Final velocity= 0 m/s
    Velocity at 2/3h= 47 m/s
    Acceleration of gravity=9.8 m/s^2
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. dont confuse yourself .. You can solve the following equations to get the max. Height :

    (47)^2 - vo^2 = 2g(2/3) ymax
    0 - vo^2 = 2g ymax

    You can as a start subtract the second equation from the first .. And keep in mind that you are using g as a vector not a scalar value in that equation ..
     
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