Finding minimum push force for a table

Click For Summary
SUMMARY

The minimum push force required to move a 20kg table with a coefficient of static friction of 0.29 is calculated using the formula for static friction. The weight of the table is 196 N, leading to a minimum push force of 57.04 N (calculated as 0.29 * 196 N). To accelerate the table at 2.5 m/s², the total required push force is 78.04 N, which includes overcoming kinetic friction (0.25 * 196 N) and providing the necessary acceleration (20kg * 2.5 m/s²).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Ability to calculate weight using the formula w=mg
  • Familiarity with free body diagrams (FBD)
NEXT STEPS
  • Learn how to draw and interpret free body diagrams (FBD)
  • Study the differences between static and kinetic friction
  • Explore the application of Newton's second law in real-world scenarios
  • Investigate the effects of varying mass on frictional force calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of friction and force calculations.

leahbender
Messages
1
Reaction score
0

Homework Statement



The coefficient of static friction between a static friction and a 20kg table and the floor is 0.29. The coefficient of kinetic friction between the same surfaces is 0.25.
How much minimum push force is required to get the table moving?
How much push force is required to accelerate the table at 2.5 m/s^2?

Homework Equations


w=mg
fk=muk+fn

The Attempt at a Solution


w=20*9.8
w= 196
At this point I'm not exactly sure how to proceed with the problem to find push force. I would appreciate any help greatly!
 
Physics news on Phys.org
leahbender said:

Homework Statement



The coefficient of static friction between a static friction and a 20kg table and the floor is 0.29. The coefficient of kinetic friction between the same surfaces is 0.25.
How much minimum push force is required to get the table moving?
How much push force is required to accelerate the table at 2.5 m/s^2?

Homework Equations


w=mg
fk=muk+fn

The Attempt at a Solution


w=20*9.8
w= 196
At this point I'm not exactly sure how to proceed with the problem to find push force. I would appreciate any help greatly!

Welcome to the PF.

In problems like this, it is usually best to start by drawing a free body diagram (FBD), showing the forces on the object being moved.

On your FBD, be sure to show all vertical and horizontal forces on the table, including the pushing force, the retarding friction force, and the weight of the table. Which version of the friction coefficient should you use for the first part of the problem when the table is not moving? What about for the moving part of the question?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
13
Views
3K
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
5
Views
5K
Replies
4
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K