Finding mole fraction of polymers from weight percents %

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SUMMARY

The discussion focuses on calculating the mole fraction of polystyrene in a blend containing 45wt% polystyrene and 55wt% polypropylene. The correct approach involves converting weight percentages to grams, determining the molar masses of polystyrene (104 g/mol) and polypropylene (42 g/mol), and then using these values to find the mole fraction. The total molar mass of the blend is 146 g/mol. A common mistake highlighted is assuming that the molar mass of the polymer is simply the sum of the individual monomer molar masses, which is only accurate for equimolar mixtures.

PREREQUISITES
  • Understanding of mole fraction calculations
  • Knowledge of molar mass determination
  • Familiarity with weight percent conversions
  • Basic concepts of polymer chemistry
NEXT STEPS
  • Study mole fraction calculations in polymer blends
  • Learn about the differences between monomer and polymer molar masses
  • Research the implications of weight percent in chemical mixtures
  • Explore advanced topics in polymer chemistry and molecular weight averages
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Chemistry students, particularly those studying polymer science, and educators looking for examples of mole fraction calculations in blends will benefit from this discussion.

watsup
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Watsup! I'm taking this nano class which is awesome but I am getting stuck on the gen chem material! no bueno. just want to make sure i did this right. Thanks!

Homework Statement

[/B]
"A blend contains 45wt% polystyrene and 55wt% polypropylene. What is the mole fraction of polystyrene in the blend?"

The Attempt at a Solution


I think I remember having to change the percents into grams,
then find the molar masses of the total blend and the polystyrene.
Then divide the grams by the molar masses leaving moles/moles --> so unitless
____________________________________________________________________

45[g(PS)]/100[g(total)]
Polystyrene: (12*8 + 1*8) = 104[g/mol]
Polypropylene: (12*3 + 6*1) = 42[g/mol]
total= 146[g/mol]

(45/104)/(100/146) ≈ 0.632
 
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This is at least strange. Unless they mean something else than they asked, to calculate molar fraction you need to know molar mass - of the polymer, not of the monomer.

Unless for some reason they decided to use a definition of molar fraction that is different from the definition used in general chemistry.
 
Why wouldn't the molar mass for the polymer be the sum of the molar masses of the two different monomers?
 
Molar mass depends on how many monomers reacted when producing one polymer molecule. And it is (almost) never a strict value, it is an average.
 
You are using 100g of polymer in your calculation. You have determined that 45g of this is PS. Where you went wrong is with the factor 100/146. You assume here that the molecular wt of the polymer is the algebraic sum of the molecular weights of the individual monomers. This would be true only for a polymer derived from an equimolar mixture of the two monomers.
 

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