Finding Momentum with Uniform Magnetic Field: q, B, a, d

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Homework Help Overview

The problem involves a charged particle moving through a uniform magnetic field and its deflection due to the Lorentz force. Participants are tasked with determining the momentum of the particle in relation to its charge, magnetic field strength, and displacements in both x and y directions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the right-hand rule to determine the charge of the particle and question the appropriateness of the momentum equation provided. There are attempts to relate the displacements to the momentum, with some participants suggesting the need for a different approach to account for the particle's trajectory.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem setup. Some guidance has been offered regarding the need to derive a new equation for the y displacement, while others express uncertainty about the applicability of circular motion equations in this context.

Contextual Notes

There is a noted lack of clarity regarding the radius of the particle's path, as participants debate whether the scenario can be treated as circular motion despite the absence of a well-defined radius.

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Homework Statement


A particle of charge q enters a region of uniform magnetic field B (pointing into the page). The field deflects a particle a distance d above the original line of flight. Is the charge positive or negative? In terms of a, d, B, and q, find the momentum of the particle.

x displacement is a
y displacement is d
particle is initially moving in the x direction

Homework Equations


p = QBR


The Attempt at a Solution


Charge is +q via the right hand rule with the magnetic field pointing into the page and force initially upward.

I'm just not sure how to find the radius. I tried finding a reference somewhere so if someone knows a good place to find the trig on this that would be great.
 
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That equation won't work in this situation (it applies to circular motion, e.g. in a cyclotron or something). Write out an equation for the y displacement... try to squeeze the x-displacement into it, then work that into momentum.
 
Isn't this situation a cyclotron except that there is no velocity in the direction along the magnetic fields axis (which is normally conserved) and there is no electric field so the particle is just spinning in a circle. My professor derived this equation with a similar problem so I'm pretty sure it is applicable.
 
Its the exact same conditions/setup... but the particle isn't moving in a circle. So there is no well-defined radius.
 

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