Particle in a uniform magnetic field

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SUMMARY

A particle with charge q and kinetic energy K moving in a uniform magnetic field of magnitude B follows a circular path of radius R. The correct expressions for speed, v, and mass, m, can be derived using the equations K=1/2mv^2 and F=qvB=(mv^2)/R. The attempt to derive the velocity as v=(2K)/(qBR) is incorrect because it does not account for the relationship between kinetic energy and the magnetic force acting on the particle. The correct approach requires a proper application of the equations of motion in a magnetic field.

PREREQUISITES
  • Understanding of classical mechanics, specifically kinetic energy and circular motion.
  • Familiarity with electromagnetic theory, particularly the Lorentz force law.
  • Knowledge of algebraic manipulation of equations.
  • Basic understanding of the relationship between force, mass, and acceleration.
NEXT STEPS
  • Study the derivation of the Lorentz force law in electromagnetic fields.
  • Learn about the relationship between kinetic energy and motion in magnetic fields.
  • Explore advanced topics in circular motion and forces acting on charged particles.
  • Investigate the effects of special relativity on charged particles in magnetic fields.
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of charged particles in magnetic fields.

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Homework Statement


A particle with charge q and kinetic energy K travels in a uniform magnetic field of magnitude B. If the particle moves in a circular path of radius R, find expressions for speed, v, and mass, m.. (Use any variable or symbol stated above as necessary.)

Homework Equations


K=1/2mv^2 F=qvB=(mv^2)/R

The Attempt at a Solution


2K=mv^2 ---> qvB=(2K)/R ---> (2K)/(qBR)

Why is this incorrect?
 
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If this is supposed to be the velocity, it looks correct (if we do not include special relativity).
Why do you think it is incorrect?
 

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