Finding no. of combinations for the situation

Click For Summary
The discussion revolves around calculating the number of combinations for a scoring scenario involving correct and incorrect answers. It establishes that if 7 out of 10 questions are answered correctly, the total score can be expressed as 4x - 10, leading to the conclusion that x must equal 7 for a score of 18. The number of ways to choose 7 correct answers from 10 is calculated as 10C7, resulting in 120 combinations. Additionally, the discussion highlights the importance of considering the combinations for selecting the 3 incorrect answers, which ultimately leads to a total of 3240 combinations. The final answer confirms the correct interpretation of the problem.
ubergewehr273
Messages
139
Reaction score
5

Homework Statement


Refer the image

Homework Equations


Equations for permutations and combinations

The Attempt at a Solution


Let x be the no. of questions that turned out to be correct. So total score will be 3x-(10-x)=4x-10.
The value of this expression must be from the given set and since x is an integer, the only no. satisfying the condition from the set is 18. (4(7)-10=18).
Hence 7 questions were correct and 3 incorrect. So, no. of ways of choosing 7 questions from 10 would be 10C7 = 120. Isn't this what has been asked in the question or is it something else?
 

Attachments

  • Screenshot-2018-5-27 master_A dvi - NEST2017_A pdf.png
    Screenshot-2018-5-27 master_A dvi - NEST2017_A pdf.png
    27.8 KB · Views: 404
Physics news on Phys.org
mfb said:
Looks right.
Well the answer is 3240
 
ubergewehr273 said:

Homework Statement


Refer the image

Homework Equations


Equations for permutations and combinations

The Attempt at a Solution


Let x be the no. of questions that turned out to be correct. So total score will be 3x-(10-x)=4x-10.
The value of this expression must be from the given set and since x is an integer, the only no. satisfying the condition from the set is 18. (4(7)-10=18).
Hence 7 questions were correct and 3 incorrect. So, no. of ways of choosing 7 questions from 10 would be 10C7 = 120. Isn't this what has been asked in the question or is it something else?
Given that you have chosen 7 right answers and three wrong answers, how many ways are there to choose each of the 3 wrong answers?
 
tnich said:
Given that you have chosen 7 right answers and three wrong answers, how many ways are there to choose each of the 3 wrong answers?
Ah, good point. That makes it 3240.
 
tnich said:
Given that you have chosen 7 right answers and three wrong answers, how many ways are there to choose each of the 3 wrong answers?
Thanks I got it.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
3K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K