Finding normal force acting on an object (Fn)?

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To find the normal force acting on a 100 kg couch sliding down an adjustable ramp with an acceleration of 0.8 m/s², the gravitational force (Fg) is calculated as 981 N. The net force in the vertical direction (Fnety) is zero, leading to the equation involving the normal force (Fn) and gravitational components. The correct calculation suggests that the normal force should be approximately 959.6 N, considering the ramp's angle and assuming a frictionless plane. An alternate method yields a value of 977.73 N, indicating variations in calculation approaches. Accurate determination of the normal force is crucial for understanding the dynamics of the system.
shamma
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1. A couch with a mass of 100 kg is placed on an adjustable ramp connected to a truck.If the couch slides down the ramp with an acceleration of 0.8 m/s^2:

2. find the normal force on the couch

3. my way:
Fg=m*9.81=981
Fnety=0N
981 sin 270+f sin 180+Fn sin 90=0N
-981Fn=0
Fn=981
my ans is wrong

hint:the ans shold be (Fn=959.6N)
 
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Hmm - I get Fn = ma*cot[arc sin(a/g) = 977.73 N

Assumes frictionless plane
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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