Finding Normalization Constant for Wave Function in Limited Space?

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SUMMARY

The normalization constant for the wave function \(\Psi(x) = A \cos\left(\frac{\pi x}{2a}\right)\) in the limited space \(-a \leq x \leq a\) is determined by integrating the square of the wave function over the specified limits. The integral \(\int_{-a}^{a} |\Psi(x)|^2 dx = 1\) leads to the equation \(A^2 a = 1\), resulting in the normalization constant \(A = \left(\frac{1}{a}\right)^{1/2}\). This confirms that the limits of integration change from \(\pm \infty\) to \(-a\) and \(a\) due to the defined space constraints.

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Homework Statement



A particle may be represented in the space, [itex]-a \le x \le a[/itex], by the wave function [itex]\Psi (x) = A cos(\frac{\pi x}{2a})[/itex]. Find the normalization constant

Homework Equations



[tex]\int |\Psi (x)|^{2}dx=1[/tex]

The Attempt at a Solution



In reading the question it defines the space as being [itex]-a \le x \le a[/itex] does this in-turn change the limits of integration for the normalization from +/- infinity to +/- a? And so result in:

[tex]\int |A cos(\frac{\pi x}{2a})|^{2}dx=1[/tex]
[tex]A^{2}a=1[/tex]
[tex]A = (\frac{1}{a})^{1/2}[/tex]
 
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Yes, that's correct.
 

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