Finding number of Anions given grams

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To find the number of anions in 1.50 g of MgBr2, first convert grams to moles using the molar mass of MgBr2, which is 184.3 g/mol. The calculation involves determining the total moles of MgBr2, then recognizing that each formula unit contains two bromide ions (Br-). The correct calculation yields approximately 9.81 x 10^21 anions, indicating that the initial calculation was incorrect due to not accounting for the two anions per formula unit. Understanding the mole-to-mole ratio is essential for accurate results in such stoichiometric problems.
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Homework Statement


How many anions are there in 1.50 g of MgBr2

Homework Equations

The Attempt at a Solution



1.5 g MgBr2 x (1 mol MgBR2/184.3 g MgBr2) x (6.022 x 1023 anions/mol)

which gave me answer of 4.91 x 1021

the correct answer is 9.81 x 1021

am i missing a step, or do i have to create a balanced equations? and use a mol to mol ratio?

any help is greatly appreciated.
 
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How many moles of Mg2+? How many moles of Br-?
 

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