How many anions are there in 1.50 g of MgBr2
The Attempt at a Solution
1.5 g MgBr2 x (1 mol MgBR2/184.3 g MgBr2) x (6.022 x 1023 anions/mol)
which gave me answer of 4.91 x 1021
the correct answer is 9.81 x 1021
am i missing a step, or do i have to create a balanced equations? and use a mol to mol ratio?
any help is greatly appreciated.