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## Homework Statement

How many anions are there in 1.50 g of MgBr

_{2}

## Homework Equations

## The Attempt at a Solution

1.5 g MgBr

_{2}x (1 mol MgBR

_{2}/184.3 g MgBr

_{2}) x (6.022 x 10

^{23}anions/mol)

which gave me answer of 4.91 x 10

^{21}

the correct answer is 9.81 x 10

^{21}

am i missing a step, or do i have to create a balanced equations? and use a mol to mol ratio?

any help is greatly appreciated.