1. The problem statement, all variables and given/known data A 400 g steel block rotates on a steel table while attached to a 1.20 m -long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.91 Nperpendicular to the tube. The maximum tension the tube can withstand without breaking is 60.0 N . Assume the coefficient of kinetic friction between steel block and steel table is 0.60. (Figure 1) 2. Relevant equations ∑Ft=thrust-ƒk ∑Fr=mv2/r at=αr v=ωr ωf2=ωi2+2αΔΘ 2π radians=1 revolution 3. The attempt at a solution ∑Ft=mat=4.91N-(.4kg*.6*9.81m/s2 at=2.5556kg m/s2 /.4kg at=6.839m/s2 α=6.839m/s2/1.2m α=5.324s-2 I assume radians are assumed as units in α..not sure on this point. ∑Fr=mv2/r Since 60N is the max ∑Fr can be 60N=.4kgv2/1.2m 180 m2/s2=v2 v=13.416 m/s v/r=ω 13.416m/s/1.2m ω=11.18s-1 Im assuming radians are implicit here. Again not sure. ωf2=ωi2+2αΔΘ We know ωi2 is zero so: ωf2=2αΔΘ ωf2/2α=ΔΘ (11.18s-1)2/(2*5.324s-2)=ΔΘ ΔΘ=11.73 Again I'm assuming ΔΘ is in radians. So 11.73 * (1 revolution)/(2π radians) 1.86 revolutions. My answer is wrong. That's all I got.