Finding Offspring Phenotypes from AB/ab Mating: Linkage Questions

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In a cross between individuals with genotypes AB/ab, the expected gamete distribution is 40% AB, 40% ab, 10% Ab, and 10% aB. To find the number of offspring exhibiting Ab or aB phenotypes, you would calculate the percentages of these gametes and multiply by the total number of offspring, which is 2000. Specifically, 10% Ab and 10% aB combined yield 20% of the offspring. Therefore, 20% of 2000 results in 400 offspring expected to show either Ab or aB phenotypes. This method effectively determines the expected phenotypic ratios based on the provided genetic linkage.
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Genes A/a and B/b are linked and known to be 20 map units apart. Individuals heterozygous for both of these genes (genotypes= AB/ab) were mated with each other. If there 2000 offspring from this cross, how many of the offspring would you expect to show Ab or aB phenotypes?
I know that the gametes for each individual separate into 40%AB, 40%ab, 10%Ab, and 10% aB, but I'm confused on how to find the number of offspring from these percentages. If someone could help it would be much appreciated!
 
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I moved the thread to the homework section.

Just multiply the fractions with 2000?
 

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