Finding Offspring Phenotypes from AB/ab Mating: Linkage Questions

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SUMMARY

The discussion focuses on calculating the expected number of offspring phenotypes from a genetic cross involving linked genes A/a and B/b, which are 20 map units apart. Given the gamete frequencies of 40% AB, 40% ab, 10% Ab, and 10% aB, the calculation for the expected number of Ab and aB phenotypes from 2000 offspring is straightforward. By multiplying the respective percentages by the total number of offspring, one can determine the expected counts for each phenotype. Specifically, this results in 200 offspring showing the Ab phenotype and 200 offspring showing the aB phenotype.

PREREQUISITES
  • Understanding of basic genetics and Mendelian inheritance
  • Familiarity with genetic linkage and map units
  • Knowledge of gamete formation and phenotype ratios
  • Basic arithmetic for calculating expected values
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  • Study genetic linkage and recombination frequency calculations
  • Learn about Punnett squares for predicting offspring ratios
  • Explore the concept of map units in genetics
  • Investigate more complex genetic crosses involving multiple traits
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This discussion is beneficial for genetics students, educators, and researchers interested in understanding inheritance patterns and calculating expected offspring phenotypes in linked genes.

fightboy
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Genes A/a and B/b are linked and known to be 20 map units apart. Individuals heterozygous for both of these genes (genotypes= AB/ab) were mated with each other. If there 2000 offspring from this cross, how many of the offspring would you expect to show Ab or aB phenotypes?
I know that the gametes for each individual separate into 40%AB, 40%ab, 10%Ab, and 10% aB, but I'm confused on how to find the number of offspring from these percentages. If someone could help it would be much appreciated!
 
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I moved the thread to the homework section.

Just multiply the fractions with 2000?
 

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