Finding particle one's final velocity in inelastic collision

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SUMMARY

The final velocity of particle one after an inelastic collision with a stationary particle can be calculated using the conservation of momentum principle. Given particle one has a mass of 6.7 kg and an initial velocity of 7.3 m/s, and collides with a stationary particle of mass 4 kg, the final velocity (vf) is determined to be 4.57 m/s. The formula used is vf = (m1 * vi1) / (m1 + m2), confirming that both particles move together post-collision.

PREREQUISITES
  • Understanding of conservation of momentum in collisions
  • Basic knowledge of inelastic collisions
  • Ability to perform calculations involving mass and velocity
  • Familiarity with the formula for final velocity in inelastic collisions
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  • Study the principles of conservation of energy in elastic vs. inelastic collisions
  • Learn about momentum conservation in multi-particle collisions
  • Explore real-world applications of inelastic collisions in physics
  • Review examples of collision problems in physics textbooks
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators seeking to explain inelastic collisions and momentum conservation.

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Homework Statement


particle 1 with mass 6.7 kg going 7.3 m/s collides inelastically with a particle of mass 4 kg at rest. find the final velocity of particle one after the collision.


Homework Equations


Ki = Kf
but, mechanical energy is not conserved in an inelastic collision.
pi = pf (initial momentum = final momentum): mvi = mvf


The Attempt at a Solution


I decided to use the conservation of momentum because it is always conserved (at least for the problems I am dealing with).

m1vi1 + m2vi2 = (m1 + m2)vf
vi2 = 0
i have both particles at the same final velocity because they buckle together after the collision, therefore they share the same velocity.

vf = m1vi1/(m1 + m2) = (6.7*7.3)/(6.7 + 4) = 4.57 m/s

Is this correct?
 
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