Finding particular solution coefficients in AC circuits with phase shift

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asi123
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Ok, let's say I have a first order circuit with i_s = Acos(wt+phase) (like in the pic).
I'm having problem with the private solution, let's say I pick my private solution like this:
i_p = Bcos(wt + phase) = Ccos(wt) + Dsin(wt) (right?)
After I place this i_p in the equation I come up with this:
f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt+phase) (right?)
Can I say
f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt)?
I mean, How do I come up with C and D?

10x in advance.
 
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  • Handwritten circuit schematic: a current source is_s(t) = A cos(wt + phi) in parallel with a switch (marked t = 0), an inductor L with i_L(0) = 0, and a resistor R with voltage v_R(t) and current i_R(t) labeled.
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I'm afraid I'm not understanding your question. What is i_p, f[C,D} and g[C,D]?
 
asi123 said:
Ok, let's say I have a first order circuit with i_s = Acos(wt+phase) (like in the pic).
I'm having problem with the private solution, let's say I pick my private solution like this:
i_p = Bcos(wt + phase) = Ccos(wt) + Dsin(wt) (right?)
After I place this i_p in the equation I come up with this:
f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt+phase) (right?)
Can I say
f[C,D]*cos(wt) + g[C,D]*sin(wt) = Acos(wt)?
I mean, How do I come up with C and D?

10x in advance.

You must develop [tex]Acos(\omega t + \phi) = A_1cos(\omega t) + A_2sin(\omega t)[/tex]

Now, [tex]f[C,D] = A_1[/tex] and [tex]g[C.D] = A_2[/tex]