Finding pH given molarity and volume

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SUMMARY

The discussion centers on calculating the pH of a solution formed by mixing 50 ml of 0.004M H2CrO4 with 50 ml of 0.005M HNO3. It is established that HNO3 is a strong acid that dissociates completely, contributing 0.00025 moles of H+ ions. In contrast, H2CrO4 is a weak acid, requiring the use of its dissociation constant (Ka) for accurate pH calculation. The final pH is determined to be approximately 2.6, emphasizing the dominance of the strong acid in the solution.

PREREQUISITES
  • Understanding of acid-base chemistry, specifically strong and weak acids.
  • Knowledge of molarity calculations and how to find moles from volume and concentration.
  • Familiarity with the concept of dissociation constants (Ka) for weak acids.
  • Ability to perform logarithmic calculations for pH determination.
NEXT STEPS
  • Research the dissociation constant (Ka) for H2CrO4 to understand its weak acid behavior.
  • Learn about the Henderson-Hasselbalch equation for buffer solutions.
  • Explore the concept of strong vs. weak acids and their implications in pH calculations.
  • Study equilibrium expressions and how they apply to weak acid dissociation.
USEFUL FOR

Chemistry students, educators, and anyone involved in acid-base chemistry or pH calculations will benefit from this discussion.

KaceCC
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Homework Statement


If 50ml of 0.004M H2CrO4 was combined with 50 ml of 0.005M HNO3 what is the pH of the resulting solution?


Homework Equations


Moles H3O=Moles OH ?
Formula for KA



The Attempt at a Solution


So, here's what I have so far.

I made the H2CrO4 represent the acid, and the HNO3 represent the base. I then subtracted them to get the excess, and then found the molarity of that. But I have no idea if I chose the right things to represent acids and bases, in fact I have no idea if I'm doing the right thing. Somebody please help!
 
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Both of these are acids, there is no base here.

Also, do these substances dissociate completely, or must Ka be taken into account?

p.s. Welcome to Physics Forums :smile:
 
Last edited:
I believe HNO3 is a strong acid- you can assume that dissociates completely. However, the other acid is NOT a strong acid--you will need Ka for that.

BUT. I'm assuming since the Ka is very small, adding the H+ ions from that species will not change the # of H+ you get from HNO3 because of sig figs.

Therefore, .05L x .005M H+ (from the complete dissociation of HNO3) = 0.00025mol H+

next, find the molarity. 100ml total = .1L
.0025 Molar H+
-log .0025 = 2.6 = pH
 
Last edited:
cadillac said:
the Ka is very small

No.

.0025 Molar H+

No.

-log .0025 = 2.6 = pH

No.
 
so sad... haha
 
Hell of a thread here.
 
Look up Ka for H2CrO4, and set up the equilibrium equation. That is the key here.
 

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