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## Homework Statement

pH fluctuations need to be determined at a maximum dosage of 50mg/L of 93% sulphuric acid .

## Homework Equations

If the start pH of the water sample is 8, how much will pH be lowered by adding of 50mg/L of 93% sulphuric acid, and what is the correlation between the different mass/volumes added and pH fluctuations.

## The Attempt at a Solution

First, I have tried to find out what would be the pH of 50mg/l of 93% H2SO4 and from given data i have calculated molarity:

Concentration * Density or Specific Quantity / Molar Mass = Molarity

(0.930) *(0.05g/L):( 98.079 g/mol)=0.0004741

H2SO4 --> 2 H+ + SO4-2

H2SO4 is a strong acid so concentration of [H+]=Molarity

**pH**=-log[H+]=-log(2x0.0004741)=

**3.0231**

However, this is where the calculation stops, since i don't know how to calculate the final pH

I am even wondering was this right way to start the calculation..

Please help... Thank you!