Finding Power Ratio of Two Pulley Systems

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SUMMARY

The discussion centers on calculating the power ratio of two pulley systems using the equation P1/P2 = τ1ω1/τ2ω2. The relationship between tensions T1 and T2 is established as T1/T2 = r1/r2, leading to the conclusion that the power ratio simplifies to (r1/r2)². However, a critical correction is noted regarding the assumption that (ω1/ω2) equals vr1/vr2, emphasizing that this relationship does not hold true. The final answer for the power ratio is confirmed as 1.

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  • Understanding of torque (τ) and angular velocity (ω)
  • Familiarity with pulley systems and their mechanics
  • Knowledge of ratios and proportions in physics
  • Basic algebra for manipulating equations
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henry3369
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Homework Statement


Part C:
http://imgur.com/mFlXGZs

Homework Equations


Power = τω

The Attempt at a Solution


P1/P2 = τ1ω1/τ2ω2 = (T1/T2) * (ω1/ω2)
T1/T2 is found in part B: r1/r2
(ω1/ω2) = vr1/vr2 (velocities are the same) = (r1/r2)
(r1/r2)*(r1/r2) = (r1)^2/(r2)^2

The answer is 1.
 
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henry3369 said:
(ω1/ω2) = vr1/vr2 (velocities are the same) = (r1/r2)

Check this. See part (A). (ω1/ω2) ≠ vr1/vr2
 

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