Relationship of acceleration in two-pulley system

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jake jungle
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Homework Statement


upload_2015-2-4_20-24-52.png

What is the relationship between a1 and a2
A.a1=a2
B.a1=2a2
C.a2=2a1
D.a1=a2√2
E.a2=a1√2
F.There is no simple relationship between the two acceleration

Homework Equations


a = F/m

The Attempt at a Solution


I am quite confused with the second pulley , so the weight of m2 is divided to 2 tension through the second pulley , but i can't find what is the magnitude of the upper tension ,therefore we can't find the lower tension or the acceleration either.
So i choose F as my answer , however i am not sure . Is my answer right ?.
 
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DEvens said:
Conserve string.

sorry i don't get it . can you be more specific , and which answer do you choose :D
 
That's where i was confused.
If m2 goes a distance of x. Will m1 goes a distance of x/2 or 2x?
 
jake jungle said:
That's where i was confused.
If m2 goes a distance of x. Will m1 goes a distance of x/2 or 2x?
Let the lengths of the horizontal portions be x (on the left), y (top right), z (lower right).
What equations relate them?
 
I have the same problem too
haruspex said:
Let the lengths of the horizontal portions be x (on the left), y (top right), z (lower right).
What equations relate them?

I think that it is Δx = Δy + Δz
Since Δy is the same as Δz, so Δx = 2Δy = 2Δz
So, a2 = 2a1, right ?
 
BvU said:
Try again.
Hmm..
I tried and got the same answer, a2 = 2a1
Please explain the correct answer to me

EDIT :
Tried again and get a1 = 2a2
 
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terryds said:
Hmm..
I tried and got the same answer, a2 = 2a1
Please explain the correct answer to me

EDIT :
Tried again and get a1 = 2a2

sr i didnt understand , since S = 1/2 at^2
then if Δx=2Δy .
then ax should be equal 2 ay ?
then a2 = 2a1 ?