Finding pressure with given radius

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The discussion revolves around calculating pressure in a test tube filled with water being spun in an ultracentrifuge. The pressure at any radius r is derived from the formula P = 1/2 (ρ)(ω)^2 + P(atm), where ρ is the density of water and ω is the angular velocity. A specific example is provided with ω = 3.8 x 10^5 rad/s and r(0) = 10 cm, prompting a calculation for pressure at r = 13 cm. The conversation also touches on whether the pressure being calculated is gauge pressure or atmospheric pressure, indicating a potential confusion in terminology. The initial approach to solving the problem involves substituting centripetal acceleration into the pressure equation, but the results do not align with the expected answer.
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Homework Statement


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A Test tube filled with water i being spun around in an ultracentrifuge with constant angular velocity, w (w = omega). The test tube i slying along a radius and revolving in a horizontal plane. The free surface of the water is at radius r(0) (with smaller parenthesis) as shown

a) show that the pressure at any raidus r within the tube is given by: P=1/2 (row)(omega)^2+P(atm)

b)suppose that w=3.8x10^5 rad/s and r(0)=10cm, what is pressure at r=13
Does it matter whether it's gauge or atmospheric pressure?

question, is it asking whether gauge pressure and actually pressure are the same?

Homework Equations


centripetal accleration =v^2/r = r(omega)^2
Pressure= P(atm) + (row)*g*h
where row is density, g is gravity (or acceleration in this case), and h is dept
density = (row) = m/V = mass over volume



The Attempt at a Solution


took simple approach
a= r(omega)^2

and used this "a" (acceleration) as"g" (gravity)
and r-r(0) (since that's the dept of watr) as h
so using Pressure= P(atm) + (row)*g*h
P= P(atm) + (density of water)*r*(omega)^2*(r-r(0))
in symbols :P
P= P(atm)+p*r*w^2(r-r(0))
but this doesn't match the answer ;)
 
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This is how I would start, does this work?
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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