Ilikebugs Messages 94 Reaction score 0 Thread starter Apr 13, 2017 #1 I don't know where to start, can I find out side lengths?View attachment 6538 Attachments potw 6.png 11.2 KB · Views: 131
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Apr 13, 2017 #2 I would let $h$ be the height of the cuboid...and so the volume $V$ is given by: $$V=100xyh$$ Now, if $w$ and $\ell$ are the width and length respectively, we know: $$w=\frac{3y}{h}$$ $$\ell=\frac{\dfrac{x}{3}}{h}$$ Multiplying these two equations together, we obtain: $$\ell w=\frac{xy}{h^2}$$ Now, the volume is also given by: $$V=\ell wh$$ Can you now get the volume in terms of $x$ and $y$ alone?
I would let $h$ be the height of the cuboid...and so the volume $V$ is given by: $$V=100xyh$$ Now, if $w$ and $\ell$ are the width and length respectively, we know: $$w=\frac{3y}{h}$$ $$\ell=\frac{\dfrac{x}{3}}{h}$$ Multiplying these two equations together, we obtain: $$\ell w=\frac{xy}{h^2}$$ Now, the volume is also given by: $$V=\ell wh$$ Can you now get the volume in terms of $x$ and $y$ alone?
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Apr 13, 2017 #4 Ilikebugs said: V=100(x^2)/2y? We have: $$V=100xyh=\ell wh$$ Thus: $$100xy=\ell w=\frac{xy}{h^2}\implies h^2=\frac{1}{100}\implies h=\frac{1}{10}$$ Hence: $$V=100xyh=100xy\cdot\frac{1}{10}=10xy$$
Ilikebugs said: V=100(x^2)/2y? We have: $$V=100xyh=\ell wh$$ Thus: $$100xy=\ell w=\frac{xy}{h^2}\implies h^2=\frac{1}{100}\implies h=\frac{1}{10}$$ Hence: $$V=100xyh=100xy\cdot\frac{1}{10}=10xy$$