I would let $h$ be the height of the cuboid...and so the volume $V$ is given by:
$$V=100xyh$$
Now, if $w$ and $\ell$ are the width and length respectively, we know:
$$w=\frac{3y}{h}$$
$$\ell=\frac{\dfrac{x}{3}}{h}$$
Multiplying these two equations together, we obtain:
$$\ell w=\frac{xy}{h^2}$$
Now, the volume is also given by:
$$V=\ell wh$$
Can you now get the volume in terms of $x$ and $y$ alone?