Calculating the Height of a Trapezium Using Given Side Lengths

[mathlearn]

View attachment 5786

AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.

 

[Prove It]

AB = (x + 3) cm, DC = (2x − 3) cm and BE = EC.

area of the trapezium is 15 cm^2 \therefore,(x + 3) (2x − 3) or ? i think you should find the are and use the squarootcan you help me to proceed.

Not even close.

The formula for the area of a trapezium is $\displaystyle \begin{align*} A = \frac{1}{2}\,\left( a + b \right) \,h \end{align*}$, where a and b are the parallel sides and h is the height.

Can you get an expression for the height in terms of x?