Finding Sigma(12^12) - Number Theory

[AH05]

Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.

 

[HallsofIvy]

Let n=12^12. Find sigma(n).

sigma(n) = the sum of the positive divisors of n.

Okay- your serve! What have you done on this yourself?

 

[AH05]

Well, I set it up:

12^12 = (3^12)(4^12) = (3^12)(2^24)

sigma(12^12) = (1-2^25)/(1-2) * (1-3^13)/(1-3)