Product of divisors number theory problem

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SUMMARY

The discussion focuses on proving the product of the divisors of a number \( n \) using mathematical induction. The established formula states that the product of the divisors of \( n \) equals \( n^{(\text{number of divisors of } n)/2} \). Participants highlight the challenge in the induction step, particularly when transitioning from \( k \) to \( k+1 \), noting that \( k \) and \( k+1 \) are relatively prime. Alternative approaches to induction, such as focusing on the number of divisors or prime factors, are suggested for a more effective proof.

PREREQUISITES
  • Understanding of mathematical induction
  • Familiarity with divisor functions
  • Knowledge of prime factorization
  • Basic number theory concepts
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  • Explore divisor functions and their properties
  • Learn about prime factorization and its applications in number theory
  • Investigate alternative proof techniques in number theory
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Students of mathematics, particularly those studying number theory, educators teaching induction methods, and anyone interested in advanced mathematical proofs.

lei123
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Homework Statement


prove using induction:
for any n =1,2,3...
the product of the divisors of n = n^(number of divisors of n (counting 1 and n)/2)


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The Attempt at a Solution


I understand why this is the case, but I'm having trouble with the induction step.
if the product of the divisors of k = k^(number of divisors of k/2), the the product of the divisors of k+1 = k^(number of divisors of k+1/2). I know that k and k+1 are relatively prime, so all their divisors are different. But I can't seem to make that final connection
 
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hi lei123! :smile:

i've no idea why anyone would want to prove it by induction :confused:

but if you do, then as you say, using induction on the number n itself won't work, so how about doing it on the number of divisors, or on the number of prime factors?
 

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