Finding tangential speed to maintain an angle theta

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To maintain a horizontal circular motion with a string at an angle theta from the vertical, the required tangential speed, v, can be derived using the equations T = mg/cos(theta), r = Lsin(theta), and a_c = v^2/r. The inward radial force is identified as mgtan(theta), which is crucial for determining the necessary speed. To find the time for one complete revolution, the circumference of the circle, given by 2πLsin(theta), is divided by the constant speed v. The kinematic equation needed for this calculation relates distance, speed, and time, allowing for the determination of the period of revolution. Understanding these relationships is essential for solving the problem effectively.
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1.
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What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always making an angle theta from the vertical?
Express your answer in terms of some or all of the variables m, L, and theta, as well as the acceleration due to gravity g.




2. I figured out the following:

T = mg/cos(theta)
r = Lsin(theta)
a_c = v^2/Lsin(theta)




3. see above

I next had to get the horizontal (inward radial) force, which is mgtan(theta). How was that force obtained? Also, how do I use this information to answer the question?
 
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Second part of question: How long does it take the bob to make one full revolution (one complete trip around the circle)?

I know that the speed is constant = sqrt[Lgsin(theta)tan(theta), and I also know the distance is the circumference of the circle = 2*pi*Lsin(theta). I know I have to use kinematics but which equation?
 
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