Finding temperature of 270g argon at 160kPa and 1.3m³

[thermo15378]

Homework Statement

two hundred seventy grams of argon at a pressure of 160kpa and a volume of 1.3 m^3.

Homework Equations

pv=nrt

The Attempt at a Solution

(160^3)(1.3) = (.27)(8.31)(t)

208=2.2437t
t=92.7

 

[Andrew Mason]

Homework Statement

two hundred seventy grams of argon at a pressure of 160kpa and a volume of 1.3 m^3.

Homework Equations

pv=nrt

The Attempt at a Solution

(160^3)(1.3) = (.27)(8.31)(t)

208=2.2437t
t=92.7

Not quite. n is the number of moles. How many moles of argon in .27 kg of argon?

AM

 

[thermo15378]

0.0067 is what i get for moles but when i plug in the formula I am getting 3649.12 and that cannnot be right.

 

[Andrew Mason]

0.0067 is what i get for moles but when i plug in the formula I am getting 3649.12 and that cannnot be right.

What is the mass of one mole of Argon?

AM