Finding Tension and Angle for a Child's Indoor Swing

  • Thread starter Thread starter bcd201115
  • Start date Start date
  • Tags Tags
    Angle Tension
Click For Summary

Homework Help Overview

The problem involves a child's indoor swing modeled as a rope of length L with a mass m at the end, swinging in a horizontal circle at a constant speed v. The task is to determine the tension T in the rope and the angle θ it makes with the vertical, given the period τ of the swing.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of centripetal acceleration concepts and suggest using Newton's second law (F = ma) for both horizontal and vertical components to derive equations related to tension and angle.

Discussion Status

Participants are engaging in a back-and-forth dialogue, exploring how to set up the equations needed to find the tension and angle. Some guidance has been provided regarding the use of two equations with two unknowns, but no consensus or resolution has been reached yet.

Contextual Notes

The problem setup assumes knowledge of centripetal acceleration and the period of motion, but specific values or additional constraints have not been provided in the discussion.

bcd201115
Messages
20
Reaction score
0

Homework Statement


A child's indoor swing consists of a rope of length L anchored to the ceiling, with a seat at the lower end. The total mass of the child and seat is m. They swing in a horizontal circle with constant speed v. As they swing around, the rope makes a constant angle θ with the vertical. Assuming the time τ for one revolution (i.e., the period) is known, find the tension T in the rope and the angle θ.


Homework Equations


Sorry i know this is a long worded problem but can anyone give me a hand getting started with this one? It's centripetal acceleration problem right?


The Attempt at a Solution

 
Physics news on Phys.org
welcome to pf!

hi bcd201115! welcome to pf! :smile:
bcd201115 said:
… It's centripetal acceleration problem right?

yup!

do F = ma twice, once for horizontal and once for vertical …

what do you get? :smile:
 
but how does that help me get the tension in the rope?
 
The tension keep the child from falling to the ground AND keep her swing in a circle.
 
tiny-tim said:
do F = ma twice, once for horizontal and once for vertical …
what do you get? :smile:
bcd201115 said:
but how does that help me get the tension in the rope?

the tension T and the angle θ are both in both equations,

so you have two equations with two unknowns … which you can solve!

show us what you get :smile:
 

Similar threads

Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K