Finding tension and hinge forces for a hanging sign on a beam

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A shop sign weighing 206 N is supported by a uniform 132 N beam of length L = 1.89 m as shown in figure below.

The guy wire is connected D = 1.19 m from the backboard. Find the tension in the guy wire. Assume theta = 43.0 o
Find the horizontal force exerted by the hinge on the beam.
Find the vertical force exerted by the hinge on the beam. Use "up" as the positive direction.

I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)

Fx = Hx -T cos(43) = 0
Hx = T cos(43)
Fy = Hy -mg + Tsin(43) = 0
Hy = mg - Tsin(43)

But these are incorrect. Where did I go wrong?
 
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"I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)"

This is complete nonsense!

You have 3 forces creating torques about the hinge. Which, and where do they act?
 
That wasn't suppose to be torque but rather tension.
 
It's still nonsense, since your units don't match (T and TL have not the same units)