Finding terms in arithmetic progressions

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This discussion focuses on solving problems related to arithmetic progressions and recursively defined sequences. The first problem involves distributing a total of $36,000 in bonuses among five salespeople, with the fifth receiving $6,000 and a constant difference in bonuses. The second problem defines a recursive sequence where the first term is 3, and each subsequent term is calculated as five times the previous term minus two. The third term of this sequence is determined to be 63.

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3). A company is to distribute \$36,000 in bonuses to its top five sales people. The fifth salesperson on the list will receive \$6,000 and the difference in bonus money between successively ranked salespeople is to be constant. find the bonus for each salesperson.

4). Find the third term of the recursively defined infinite sequence.
[a][/1]=3 [a][k+1]=[5][/ak]-2
 
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doreent0722 said:
3). A company is to distribute \$36,000 in bonuses to its top five sales people. The fifth salesperson on the list will receive \$6,000 and the difference in bonus money between successively ranked salespeople is to be constant. find the bonus for each salesperson.

4). Find the third term of the recursively defined infinite sequence.
[a][/1]=3 [a][k+1]=[5][/ak]-2

The sum of an arithmetic sequence is given by $$S_n = \dfrac{n}{2}(2a+(n-1)d)$$ where $$n$$ is the number of terms, $$a$$ is the first term and $$d$$ is the common difference.

You're given values for $$S_n$$, $$a$$ and $$n$$ in the question
 
Hello, doreent0722!

4) Find the third term of the recursively defined infinite sequence.
. . a_1=3,\;\;a_{k+1} = 5a_k -2
Do you understand what you are given?

The first term is 3.
Thereafter, each term is 5 times the preceding term, minus 2.

. . \begin{array}{ccccccc} a_1 &=& 3 \\ a_2 &=& 5(3)-2 &=& 13 \\ a_3&=& 5(13) - 2 &=& 63 & {\color{red}\Longleftarrow} \\ a_4 &=& 5(63)-2&=& 313 \\ a_5 &=& 5(313)-2 &=& 1563 \end{array}
 

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