Finding the angle of 3-dimensional vectors.

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To find the angle between two 3-dimensional vectors, the scalar (dot) product is used. For vectors A and B, the dot product is calculated as A · B = |A||B|cos(θ). By determining the dot product and the magnitudes of both vectors, the angle θ can be found by taking the arccosine of the result. The example provided illustrates this method with specific vector components. This approach effectively calculates the angle between the two vectors.
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How would the angle between two vectors be found, if, for each vector, three components (i, j, k) were given?

Ex. Given that vector A = 2.0 i + 4.0 j - 7.0 k and vector B = 5.0 i - 3.0 j + 1.0 k, what is the angle between A and B?
 
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Use the definition of the scalar (dot) product.
 
Last edited:
Ok.

We can find it by dot product.We know that for two vectors A and B

\vec{A} \cdot \vec{B} = AB\cos\theta

Hence find A dot B and divide it by AB. And take its arccosine and you will get your angle.
 
...dot...product?

All right. I'm pulling out some of my old Pre-Cal stuff, when I learned that. :DDD

Thank you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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