1. The problem statement, all variables and given/known data Vectors A and B have equal magnitudes of 4.93. If the sum of A and B is the vector 6.79j, determine the angle between A and B 2. Relevant equations c^2 = a^2 + b^2 -2abcos(theta) 3. The attempt at a solution I just rearranged the formula above so that I could solve for the angle. I keep getting the same answer (87.0 or 87.1 degrees) but its still wrong. Is it the fact that the sum is 6.79j with j meaning something? I know its a unit vector that indicates direction but I wasn't too sure. Please help!!