Finding the Angle of Incidence for Light Inside a Prism

[MCATPhys]

a ray of light enters a prism in the shape of an isosceles right triangle perpendicular to its surface. the light enters through one of the legs and the index of refraction of the prism's constituents is 1.4. where will the light go as it enters the prism?

the light enters at 0 degrees. It goes to the hypotenuse. Can someone draw me the picture of how it looks like? If it strikes less than the critical angle, then the light will pass through. But how do I find the critical angle?

 

[MCATPhys]

so i used the equation:

1.4sinx = 1sin90
so the critical angle is x = 45 degrees

But how do I find the angle of incidence for the ray inside the prism?