Finding the coefficient of friction

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To find the coefficient of friction for a box weighing 500N sliding down a ramp at a 25-degree angle, the net forces in both normal and tangential directions must be analyzed. The frictional force (Ff) can be expressed as Ff = u * Fn, where u is the coefficient of friction and Fn is the normal force. Since the box is sliding at a constant speed, the net force acting on it is zero, indicating that the gravitational component along the ramp equals the frictional force. By calculating the normal force and the gravitational force component, the coefficient of friction can be determined. Understanding the balance of forces is crucial for solving this problem effectively.
ben811
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A box that weighs 500N is sliding down a ramp at a constant speet. The angle the ramp makes with the horizontal is 25 degrees. What is the coefficient of friction between the box and the ramp?

Can anyone give me some direction in how to approach solving this? I understand that
Ff=u*Fn, but I can't figure out how to find Ff.
 
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Well, what is the NET force acting upon the box, in both the normal&tangential directions?
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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