Finding the Critical Velocity for Special Relativity Effects

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Homework Help Overview

The discussion revolves around finding the critical velocity at which the Lorentz factor, Gamma (Γ), equals 1.0100 in the context of special relativity. Participants are exploring the implications of time dilation and length contraction at speeds below this threshold.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants question the correctness of the original formula provided for Gamma and discuss alternative expressions. There is an exploration of simplifying the equations and the relevance of length in the context of the problem.

Discussion Status

The discussion has seen participants offering corrections and alternative formulations for Gamma. Some have provided suggestions for simplifying the equations, indicating a productive exchange of ideas. The original poster expresses a moment of realization, suggesting progress in understanding.

Contextual Notes

There appears to be confusion regarding the correct expression for Gamma and its application in the problem. The original poster's uncertainty about where to start indicates a potential gap in foundational knowledge or assumptions about the problem setup.

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Homework Statement


For what value of v does Gamma (G) =1.0100? Observe that for speeds lower than this value, time dilationand length contraction are effects amounting to less that 1%


Homework Equations


L=Lp/G=Lp(1-(v^2/c^2))^2


The Attempt at a Solution


I do not know where to start. Is this the correct formula, and then if it is, how would I go about solving for the Velocity?
 
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You seem to have the wrong expression for gamma, unless it's a typo.
 
The exponent on the right should be 1/2 (square root), not 2. Start with

\frac{L_p}{\gamma} = L_p \sqrt{1 - v^2 / c^2}

What can you do to simplify this equation a bit, first?
 
Why involve any lengths here? You have an equation (rather a definition) for Gamma do you not? Isn't it just

\gamma=\left( \frac{1}{1-\frac{v^2}{c^2}} \right)^{\frac{1}{2}}

If so, try squaring both sides of the equation.
 
I got it! Thank you!
 

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