Finding the Deadly Voltage for a 100uF Capacitor

[ha9981]

Homework Statement

What voltage would be dangerous for a 100uF capacitor given that a person's electrical resistance can be as low as 1kohm if the skin is wet. Does the capacitance matter? If so how?

Assuming heart stoppage happens at 500mA

Homework Equations

Current for capacitor: i = c dv/dt
Ohms law: i = v/r

The Attempt at a Solution

From what I understand the current will be dependent on how fast the voltage changes and the capacitance. So there is no answer for the 100uF question as we don't know how fast voltage changes with respect to time. But we do know that capacitance does matter and a higher capacitance can result in higher current which is more deadly.

I am having doubts though that possibly we can find a deadly voltage for a 100uF capacitor, so posting here to have get directed in the right path...

 

[ha9981]

I thought over this problem with first order response of RC circuit. And here is what I got:

time constant = RC = 1/10
V(t) = V₀ e^-10t
I(t) = V₀ /R e^-10t
Now to find initial voltage I assumed we take time as zero? In that case for 100uF capacitor with 1kohm resistance and critical current of 500mA I got 500V to be the deadly voltage.