Finding the Derivative of Factorial Function

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The discussion focuses on finding the derivative of the factorial function, represented as f(x) = x!. The user initially attempts to differentiate using an integral representation but makes an error in the differentiation process. Correctly, the derivative is given by the integral involving ln(t), specifically f'(x) = ∫₀^∞ ln(t)e^(-t)t^x dt. The participants note that there is no simple anti-derivative for this integral, indicating that numerical methods must be used for evaluation. The conversation emphasizes the complexity of integrating this expression, particularly when evaluating at specific points like f'(2).
coki2000
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Hi,
I want to find the derivative of factorial function f(x)=x! and i found this integral,

f(x)=x!=\int_{0}^{\infty}e^{-t}t^xdt when i take derivative of this

\frac{d}{dx}f(x)=\frac{d}{dx}\int_{0}^{\infty}e^{-t}t^xdt=\int_{0}^{\infty}e^{-t}t^xlnxdx

How do i find this integral? Please help me. Thanks.
 
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Incorrect differentiation!

You should get:
\frac{df}{dx}=\int_{0}^{\infty}\ln(t)e^{-t}t^{x}dt

There is no nice expression for the anti-derivative with respect to "t" here, so it must be evaluated numerically.
 
arildno said:
Incorrect differentiation!

You should get:
\frac{df}{dx}=\int_{0}^{\infty}\ln(t)e^{-t}t^{x}dt

There is no nice expression for the anti-derivative with respect to "t" here, so it must be evaluated numerically.

Okey if i want to find

f'(2)=\int_{0}^{\infty}\ln(t)e^{-t}t^{2}dt

can i integrate it?
 
coki2000 said:
can i integrate it?

Have you actually read arildno's post?
 
coki2000 said:
Okey if i want to find

f'(2)=\int_{0}^{\infty}\ln(t)e^{-t}t^{2}dt

can i integrate it?

To anything simple?

Nope.
 
coki2000 said:
Okey if i want to find

f'(2)=\int_{0}^{\infty}\ln(t)e^{-t}t^{2}dt

can i integrate it?

Yes, http://mathworld.wolfram.com/Euler-MascheroniConstant.html" .
 
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