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Finding the distance for one stone to pass the other

  1. Mar 8, 2010 #1
    1. The problem statement, all variables and given/known data
    A stone is dropped from the top of a tall cliff(with zero initial speed), and 1.00s later a second stone is thrown vertically downward w/ a speed of 16 m/s. How far below the top cliff will the second stone overtake the first

    2. Relevant equations
    distance = vot + 1/2a(tsquared)


    3. The attempt at a solution
    I attempted this so many different ways but I'm just not getting the answer. I know the vo of the first stone is zero and the acceleration is -9.8 m/s squared. I think that the second stones initial velocity is 16 m/s.
     
  2. jcsd
  3. Mar 8, 2010 #2
    answer should be 15.7 m by the way
     
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