Finding the equation of a curve given the tangent equation

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SUMMARY

The discussion centers on finding the value of c>0 such that the line y=x+1 is the tangent line to the curve defined by c√x. The mathematical approach involves setting the equations equal and transforming them into a quadratic form, specifically x^2 + (2 - c^2)x + 1 = 0. To ensure the line is tangent to the curve, the discriminant of this quadratic must equal zero, which is crucial for determining the conditions under which the curve and line intersect at exactly one point.

PREREQUISITES
  • Understanding of calculus concepts, particularly tangents and curves.
  • Knowledge of quadratic equations and their properties.
  • Familiarity with the discriminant and its role in determining the nature of roots.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Study the properties of quadratic equations, focusing on the discriminant.
  • Explore calculus concepts related to tangents and derivatives.
  • Learn how to derive equations of curves from tangent lines.
  • Practice solving problems involving tangents to curves in calculus.
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Students studying calculus, particularly those interested in understanding the relationship between tangent lines and curves, as well as educators looking for examples to illustrate these concepts.

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I have a calculus question and I am not sure where to get started. The question states:"Find the value of c>0 such that the line y=x+1 is the tangent line to the curve c√x (i.e. intersects the curve at one point and shares the same slope at that point)."
Thanks
 
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musad said:
I have a calculus question and I am not sure where to get started. The question states:"Find the value of c>0 such that the line y=x+1 is the tangent line to the curve c√x (i.e. intersects the curve at one point and shares the same slope at that point)."
Thanks

$\displaystyle \begin{align*} x + 1 &= c\,\sqrt{x} \\ \left( x +1 \right) ^2 &= \left( c\,\sqrt{x} \right) ^2 \\ x^2 + 2x +1 &= c^2\,x \\ x^2 + \left( 2 - c^2 \right) \, x + 1 &= 0 \end{align*}$

Now to have only one solution, the discriminant must be zero...
 
What is the discriminant?
 
musad said:
What is the discriminant?

You're doing calculus without knowledge of basic quadratics?
 
Prove It said:
You're doing calculus without knowledge of basic quadratics?

I do, I just think we may use different terminology so i wasnt sure what the term meant, sorry.
 
musad said:
I do, I just think we may use different terminology so i wasnt sure what the term meant, sorry.

For a quadratic of the form $\displaystyle \begin{align*} a\,x^2 + b\,x + c = 0 \end{align*}$, the roots are $\displaystyle \begin{align*} x = \frac{-b \pm \sqrt{b^2 - 4\,a\,c}}{2a} \end{align*}$. The stuff under the square root is important, because it determines whether or not there are solutions (as you can't have the square root of a negative number). It's so important, it has its own name, the DISCRIMINANT.
 

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