Finding the equation of a curve given the tangent equation

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Discussion Overview

The discussion revolves around a calculus problem involving finding the value of \( c > 0 \) such that the line \( y = x + 1 \) is tangent to the curve \( c\sqrt{x} \). Participants explore the conditions under which the line intersects the curve at one point and shares the same slope at that point.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents the problem and begins to derive the equation by equating the line and the curve, leading to a quadratic equation.
  • Another participant questions the meaning of the discriminant in the context of the quadratic equation derived.
  • There is a challenge regarding the understanding of basic quadratic terminology, with some participants expressing surprise at the lack of familiarity with the term "discriminant."
  • A later reply clarifies the definition of the discriminant and its significance in determining the nature of the roots of a quadratic equation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the understanding of the discriminant, with some expressing confusion and others providing clarification. The discussion remains unresolved regarding the initial problem and the implications of the discriminant.

Contextual Notes

There are limitations in the discussion regarding the participants' varying levels of familiarity with quadratic equations and terminology, which may affect their ability to engage with the problem fully.

musad
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I have a calculus question and I am not sure where to get started. The question states:"Find the value of c>0 such that the line y=x+1 is the tangent line to the curve c√x (i.e. intersects the curve at one point and shares the same slope at that point)."
Thanks
 
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musad said:
I have a calculus question and I am not sure where to get started. The question states:"Find the value of c>0 such that the line y=x+1 is the tangent line to the curve c√x (i.e. intersects the curve at one point and shares the same slope at that point)."
Thanks

$\displaystyle \begin{align*} x + 1 &= c\,\sqrt{x} \\ \left( x +1 \right) ^2 &= \left( c\,\sqrt{x} \right) ^2 \\ x^2 + 2x +1 &= c^2\,x \\ x^2 + \left( 2 - c^2 \right) \, x + 1 &= 0 \end{align*}$

Now to have only one solution, the discriminant must be zero...
 
What is the discriminant?
 
musad said:
What is the discriminant?

You're doing calculus without knowledge of basic quadratics?
 
Prove It said:
You're doing calculus without knowledge of basic quadratics?

I do, I just think we may use different terminology so i wasnt sure what the term meant, sorry.
 
musad said:
I do, I just think we may use different terminology so i wasnt sure what the term meant, sorry.

For a quadratic of the form $\displaystyle \begin{align*} a\,x^2 + b\,x + c = 0 \end{align*}$, the roots are $\displaystyle \begin{align*} x = \frac{-b \pm \sqrt{b^2 - 4\,a\,c}}{2a} \end{align*}$. The stuff under the square root is important, because it determines whether or not there are solutions (as you can't have the square root of a negative number). It's so important, it has its own name, the DISCRIMINANT.
 

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